It's an easy one ;)
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About Me
- sea dot
- I am a filmmaker and artist (check out the web sites below). I'm also an amateur astronomer and explorer. My artistic endeavors often draw from my scientific background. I love light in all of its forms (particularly polarized light) and I love exploring its nature through film, photography and anything else that might come along. I also love movies, movies, movies- film is my favorite storytelling medium!
2 comments:
I'm not an insomniac and I have forgotten all the maths I ever knew but is the answer: 35438 ms-1 (to 5 s.f.)????
If not, let me say your blog is interesting. I like your mixed of careers, more people should do that rather than sticking with one thing.
Close! I think you just made an order of operations mistake:
First, the numerator:
2*(6.67x10^-11)*(5.97x10^24)=7.964x10^14
Then, divide by 6.37x10^6
=1.250x10^8
Then, take the square root:
=11200 m/s or 11.2km/sec (three sig figs- since you can't have more sig figs out than you put in)
That gives us (drum roll): The minimum speed an object without propulsion needs to have to move away indefinitely from the Earth (a.k.a. escape velocity).
I think you just saved the "inside" exponents for the end, which threw off the square root! ;)
BTW- The "brazilion" joke was my favorite of the week, too!
Thanks for responding!
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